3(x^2+y^2)=10xy

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Solution for 3(x^2+y^2)=10xy equation:


Simplifying
3(x2 + y2) = 10xy
(x2 * 3 + y2 * 3) = 10xy
(3x2 + 3y2) = 10xy

Solving
3x2 + 3y2 = 10xy

Solving for variable 'x'.

Reorder the terms:
-10xy + 3x2 + 3y2 = 10xy + -10xy

Combine like terms: 10xy + -10xy = 0
-10xy + 3x2 + 3y2 = 0

Factor a trinomial.
(x + -3y)(3x + -1y) = 0

Subproblem 1

Set the factor '(x + -3y)' equal to zero and attempt to solve: Simplifying x + -3y = 0 Solving x + -3y = 0 Move all terms containing x to the left, all other terms to the right. Add '3y' to each side of the equation. x + -3y + 3y = 0 + 3y Combine like terms: -3y + 3y = 0 x + 0 = 0 + 3y x = 0 + 3y Remove the zero: x = 3y Simplifying x = 3y

Subproblem 2

Set the factor '(3x + -1y)' equal to zero and attempt to solve: Simplifying 3x + -1y = 0 Solving 3x + -1y = 0 Move all terms containing x to the left, all other terms to the right. Add 'y' to each side of the equation. 3x + -1y + y = 0 + y Combine like terms: -1y + y = 0 3x + 0 = 0 + y 3x = 0 + y Remove the zero: 3x = y Divide each side by '3'. x = 0.3333333333y Simplifying x = 0.3333333333y

Solution

x = {3y, 0.3333333333y}

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